Решение №16791: а) 11 см -7 см = 4 см, 4 см + 4 см =8 см. б) 8 см - 7 см = 1 см

Ответ: NaN

Решение №16792: а) 4*17 см - 5*13 см = 3 см. б) 4*13 см - 3*17 см = 1 см. в) Можно воспользоваться тем, что 9 см = 3* 3 см, или тем, что 9 см = 9*1 см.

Ответ: NaN

Решение №16880: \(\frac{1-\sqrt{2t}}{\frac{1-\sqrt[4]{8t^{3}}}{1-\sqrt[4]{2t}}-\sqrt{2t}}\cdot \left ( \frac{\sqrt[4]{\frac{1}{2t}}+\sqrt[4]{4t^{2}}}{1+\sqrt[4]{\frac{1}{2t}}}-\sqrt{2t} \right )^{-1}=\frac{\left ( 1-\sqrt[4]{4t^{2}} \right )\left ( 1-\sqrt[4]{2t} \right )}{1-\sqrt[4]{4t^{2}}}\cdot \left ( \frac{1+\sqrt[4]{8t^{3}}}{1+\sqrt[4]{2t}}-\sqrt[4]{4t^{2}} \right )^{-1}=\left ( 1-\sqrt[4]{2t} \right )\left ( 1-\sqrt[4]{2t}+\sqrt[4]{4t^{2}}-\sqrt[4]{4t^{2}} \right )^{-1}=\left ( 1-\sqrt[4]{2t} \right )\left ( 1-\sqrt[4]{2t} \right )^{-1}=\frac{\left ( 1-\sqrt[4]{2t} \right )}{\left ( 1-\sqrt[4]{2t} \right )}=1\)

Ответ: 1

Решение №16886: \(\left ( \frac{a+a^{\frac{3}{4}}a^{\frac{1}{2}}+a^{\frac{1}{4}}b^{\frac{3}{2}}+b^{2}}{a^{\frac{1}{2}}+2a^{\frac{1}{4}}b^{\frac{1}{2}}+b}\left ( \sqrt[4]{a}+\sqrt{b} \right )+\frac{3\sqrt{b}\left ( a^{\frac{1}{2}}-b \right )}{a^{-\frac{1}{4}}\left ( a^{\frac{1}{4}-\sqrt{b}} \right )} \right )^{-\frac{1}{3}}:\left ( \sqrt[4]{a}+\sqrt{b} \right )^{-1}=\left ( \frac{\sqrt[4]{a^{4}}+\sqrt[4]{a^{3}}\sqrt{b}+\sqrt[4]{a}\sqrt{b^{3}}+\sqrt{b^{4}}}{\sqrt[4]{a^{2}}+2\sqrt[4]{a}\sqrt{b}+\sqrt{b^{2}}}\left ( \sqrt[4]{a}+\sqrt{b} \right )+\frac{3\sqrt{b}\left ( \sqrt[4]{a^{2}}-\sqrt{b^{2}} \right )}{\frac{1}{\sqrt[4]{a}}\left ( \sqrt[4]{a}-\sqrt{b} \right )} \right )^{-\frac{1}{3}}\left ( \sqrt[4]{a}+\sqrt{b} \right )=\left ( \frac{\left ( \sqrt[4]{a^{3}}+\sqrt{b^{3}} \right )\left ( \sqrt[4]{a}+\sqrt{b} \right )}{\sqrt[4]{a}+\sqrt{b}}+3\sqrt[4]{a^{2}}\sqrt{b}\left ( \sqrt[4]{a}+\sqrt{b} \right ) \right )^{-\frac{1}{3}}\cdot \left ( \sqrt[4]{a}+\sqrt{b} \right )=\left ( \sqrt[4]{a^{3}}+3\sqrt[4]{a^{2}}\sqrt{b}+3\sqrt[4]{a}\sqrt{b^{2}}+\sqrt{b^{3}} \right )^{-\frac{1}{3}}\left ( \sqrt[4]{a}+\sqrt{b} \right )=\left ( \sqrt[4]{a}+\sqrt{b} \right )^{-1}\left ( \sqrt[4]{a}+\sqrt{b} \right )=1\)

Ответ: 1

Решение №16887: \(\frac{\left ( pq^{-1}+1 \right )^{2}}{pq^{-1}-p^{-1}q}\cdot \frac{p^{3}q^{-3}-1}{p^{2}q^{-2}+pq^{-1}+1}:\frac{p^{3}q^{-3}+1}{pq^{-1}+p^{-1}q-1}=\frac{\left ( p+q \right )^{2}}{q^{2}}\cdot \frac{pq}{p^{2}-q^{2}}\cdot \frac{p^{3}-q^{3}}{q^{3}}\cdot \frac{q^{2}}{p^{2}+pq+q^{2}}:\left ( {\frac{p^{3}-q^{3}}{q^{3}}}{}\cdot \frac{pq}{p^{2}-pq+q^{2}} \right )=\frac{\left ( p+q \right )^{2}p}{q\left ( p+q \right )\left ( p-q \right )}\cdot \frac{\left ( p-q \right )\left ( p^{2}+pq+q^{2} \right )}{q\left ( p^{2}+pq+q^{2} \right )}:\left ( \frac{\left ( p+q \right )\left ( p^{2}-pq+q^{2} \right )p}{q^{2}\left ( p^{2}-pq+q^{2} \right )} \right )=\frac{p\left ( p+q \right )}{q^{2}}:\frac{p\left ( p+q \right )}{q^{2}}=1\)

Ответ: 1

Решение №16892: \(\frac{8-m}{\sqrt[3]{m}+2}:\left ( 2+\frac{\sqrt[3]{m^{2}}}{\sqrt[3]{m}+2} \right )+\left ( \sqrt[3]{m}+\frac{2\sqrt[3]{m}}{\sqrt[3]{m}-2} \right )\cdot \frac{\sqrt[3]{m^{2}-4}}{\sqrt[3]{m^{2}}+2\sqrt[3]{m}}=\frac{\left ( 2-\sqrt[3]{m} \right )\left ( 4+2\sqrt[3]{m}+\sqrt[3]{m^{2}} \right )}{\sqrt[3]{m}+2}\cdot \frac{\sqrt[3]{m}+2}{4+2\sqrt[3]{m}+\sqrt[3]{m^{2}}}+\sqrt[3]{m}=2-\sqrt[3]{m}+\sqrt[3]{m}=2\)

Ответ: 2

Решение №16897: \(\left ( \frac{3^{\frac{3}{2}}+\frac{1}{8}z^{\frac{3}{5}}}{3+\sqrt{3}\sqrt[5]{z}+\frac{1}{4}\sqrt[5]{z^{2}}}+\frac{3\sqrt{3}\sqrt[5]{z}}{2\sqrt{3}+\sqrt[5]{z}} \right )^{-1}:\frac{1}{2\sqrt{12}+\sqrt[5]{32z}}=\left ( \frac{24\sqrt{3}+\sqrt[5]{z^{3}}}{24+8\sqrt{3}\sqrt[5]{z}+2\sqrt[5]{z^{2}}}+\frac{3\sqrt{3}\sqrt[5]{z}}{2\sqrt{3}+\sqrt[5]{z}} \right )^{-1}:\frac{1}{2\left ( 2\sqrt{3}+\sqrt[5]{z} \right )}=\left ( \frac{\left ( 2\sqrt{3}+\sqrt[5]{z} \right )^{2}}{2\left ( 2\sqrt{3}+\sqrt[5]{z} \right )} \right )^{-1}\cdot 2\left ( 2\sqrt{3}+\sqrt[5]{z}\right ) =\frac{2}{2\sqrt{3}+\sqrt[5]{z}}\cdot 2\left ( 2\sqrt{3}+\sqrt[5]{z} \right )=4\)

Ответ: 4

Решение №16907: \(\left ( -4a\sqrt[3]{\frac{\sqrt{ax}}{a^{2}}} \right )^{3}+\left ( -10a\sqrt{x}\sqrt{\left ( ax \right )^{-1}} \right )^{2}+\left ( -2\left ( \sqrt[3]{a\sqrt[4]{\frac{x}{a}}} \right )^{2} \right )^{3}=\frac{-64a^{3}\sqrt{ax}}{a^{2}}+\frac{100a^{2}x}{ax}-\frac{8a^{2}\sqrt{x}}{\sqrt{a}}=-64a\sqrt{ax}+100a-8a\sqrt{ax}=100a-72a\sqrt{ax}=100\cdot 3\frac{4}{7}-72\cdot 3\frac{4}{7}\cdot \sqrt{3\frac{4}{7}\cdot 0.28}=100\cdot \frac{25}{7}-72\cdot \frac{25}{7}\cdot \sqrt{\frac{25}{7}\cdot \frac{7}{25}}=\frac{2500}{7}-\frac{1800}{7}=\frac{700}{7}=100\)

Ответ: 100

Решение №16917: \(\left ( \sqrt[3]{\left ( \frac{1}{2} \right )^{-3}}-t^{3}+\sqrt[3]{\frac{t^{5}+2t^{4}+4t^{3}}{4-4t+t^{2}}} \right ):\left ( \frac{1}{\sqrt{2}-\sqrt{t}}+\frac{1}{\sqrt{2}+\sqrt{t}} \right )=\left ( \sqrt[3]{2^{3}-t^{3}}+\sqrt[3]{\frac{t^{3}\left ( t^{2}+2t+4 \right )}{\left ( 2-t \right )^{2}}} \right ):\left ( \frac{\sqrt{t}+\sqrt{2}+\sqrt{2}-\sqrt{t}}{\left ( \sqrt{2}-\sqrt{t} \right )\left ( \sqrt{2}+\sqrt{t} \right )} \right )=\frac{\sqrt[3]{\left ( 2-t \right )^{3}\left ( 4+2t+t^{2} \right )}+t\sqrt[3]{4+2t+t^{2}}}{\sqrt[3]{\left ( 2-t \right )^{2}}}\cdot \frac{2-t}{2\sqrt{2}}=\frac{\sqrt[3]{\left ( 2-t \right )\left ( 4+2t+t^{2} \right )}}{\sqrt{2}}=\frac{\sqrt[3]{8-t^{3}}}{\sqrt{2}}\)

Ответ: \(\frac{\sqrt[3]{8-t^{3}}}{\sqrt{2}}\)

Решение №16918: \(\left ( \left ( \frac{\sqrt{a}-1}{\sqrt{a}+1} \right )^{-1} \left (\frac{\sqrt{a}-1}{\sqrt{a}+1} \right )^{\frac{1}{2}} -\sqrt{a-1}\left ( \sqrt{a}+1 \right )^{-1}\right )\cdot \frac{1}{a^{\frac{2}{3}}+a^{\frac{1}{3}}+1}=\left ( \frac{\sqrt{a}+1}{\sqrt{a}-1}\sqrt{\frac{\sqrt{a}-1}{\sqrt{a}+1}}-\frac{\sqrt{a-1}}{\sqrt{a}+1} \right )^{-2}\cdot \frac{1}{a^{\frac{2}{3}}+a^{\frac{1}{3}}+1}=\left ( \frac{\sqrt{a}+1}{\sqrt{\sqrt{a}-1}}-\frac{\sqrt{\sqrt{a}-1}}{\sqrt{\sqrt{a}+1}} \right )^{-2}\cdot \frac{1}{\sqrt[3]{a^{2}}+\sqrt[3]{a}+1}=\left ( \frac{\sqrt{a}+1-\sqrt{a}+1}{\sqrt{a-1}} \right )^{-2}\cdot \frac{1}{\sqrt[3]{a^{2}}+\sqrt[3]{a}+1}=\left ( \frac{2}{\sqrt{a-1}} \right )^{-2}\cdot \frac{1}{\sqrt[3]{a^{2}}+\sqrt[3]{a}+1}=\frac{a-1}{4\left ( a^{2}+\sqrt[3]{a}+1 \right )}=\frac{\left ( \sqrt[3]{a}-1 \right )\left ( \sqrt[3]{a^{2}}+\sqrt[3]{a}+1 \right )}{4\left ( a^{2}+\sqrt[3]{a}+1 \right )}=\frac{\sqrt[3]{a}-1}{4}\)

Ответ: \(\frac{\sqrt[3]{a}-1}{4}\)

Решение №16920: \(\left ( \frac{\left ( 1+a^{-\frac{1}{2}} \right )^{\frac{1}{6}}}{\left ( a^{\frac{1}{2}}+1 \right )^{-\frac{1}{3}}}-\frac{\left ( a^{\frac{1}{2}}-1 \right )^{\frac{1}{3}}}{\left ( 1-a^{-\frac{1}{2}} \right )^{-\frac{1}{6}}} \right )^{-2}\cdot \frac{\frac{1}{3}a^{\frac{1}{12}}}{\sqrt{a}+\sqrt{a-1}}=\left ( \sqrt[6]{\frac{\sqrt{a}+1}{\sqrt{a}}}\sqrt[6]{\left ( \sqrt{a}+1 \right )^{2}}-\sqrt[6]{\left ( \sqrt{a}-1 \right )^{2}}\sqrt[6]{\frac{\sqrt{a}-1}{\sqrt{a}}} \right )^{-2}\frac{\sqrt[12]{a}}{3\left ( \sqrt{a}+\sqrt{a-1} \right )}=\left ( \frac{\sqrt{\sqrt{a}+1}-\sqrt{\sqrt{a}-1}}{\sqrt[12]{a}} \right )^{-2}\cdot \frac{\sqrt[12]{a}}{3\left ( \sqrt{a}+\sqrt{a-1} \right )}=\frac{\sqrt[6]{a}}{2\left ( \sqrt{a}-\sqrt{a-1} \right )}\cdot \frac{\sqrt[12]{a}}{3\left ( \sqrt{a}+\sqrt{a-1} \right )}=\frac{\sqrt[4]{a}}{6\left ( a-a+1 \right )}=\frac{\sqrt[4]{a}}{6}\)

Ответ: \(\frac{\sqrt[4]{a}}{6}\)

Решение №16922: \(\left ( \frac{1}{a+\sqrt{2}}-\frac{a^{2}+4}{a^{3}+2\sqrt{2}} \right ):\left ( \frac{a}{2}-\frac{1}{\sqrt{2}}+\frac{1}{a} \right )^{-1}=\left ( \frac{1}{a+\sqrt{2}}-\frac{a^{2}+4}{\left ( a+\sqrt{2} \right )\left ( a^{2}+\sqrt{2}a+2 \right )} \right )\cdot \frac{a^{2}+\sqrt{2}a+2}{2a}=\frac{a^{2}-\sqrt{2}a+2-a^{2}-4}{\left ( a+\sqrt{2} \right )\left ( a^{2}+\sqrt{2}a+2 \right )}\cdot \frac{a^{2}-\sqrt{2}a+2}{2a}=\frac{-\sqrt{2}a-2}{a+\sqrt{2}}\cdot \frac{1}{2a}=\frac{-\sqrt{2}\left ( a+\sqrt{2} \right )}{a+\sqrt{2}}\cdot \frac{1}{\sqrt{2a}}=-\frac{\sqrt{2}}{2a}\)

Ответ: \(-\frac{\sqrt{2}}{2a}\)

Решение №16948: \(\left ( \frac{2}{\sqrt{3}-1}+\frac{3}{\sqrt{3}-2}+\frac{15}{3-\sqrt{3}} \right )\left ( \sqrt{3}+5 \right )^{-1}=\left ( \frac{2\left ( \sqrt{3}+1 \right )}{2}+\frac{3\left ( \sqrt{3}+2 \right )}{-1}+\frac{15\left ( 3+\sqrt{3} \right )}{6} \right )\cdot \frac{1}{\sqrt{3}+5}=\frac{-4\sqrt{3}-10+15+5\sqrt{3}}{2}\cdot \frac{1}{\sqrt{3}+5}=\frac{\sqrt{3}+5}{2}\cdot \frac{1}{\sqrt{3}+5}=\frac{1}{2}\)

Ответ: \(\frac{1}{2}\)

Решение №16951: \(\frac{\sqrt{c-d}}{c^{2}\sqrt{2c}}\left ( \sqrt{\frac{c-d}{c+d}}+\sqrt{\frac{c^{2}+cd}{c^{2}-cd}} \right )=\frac{\sqrt{c-d}}{c^{2}\sqrt{2c}}\left (\sqrt{\frac{c-d}{c+d}}+\sqrt{\frac{c\left ( c+d \right )}{c\left ( c-d \right )}} \right )=\frac{\sqrt{c-d}}{c^{2}\sqrt{2c}}\left ( \sqrt{\frac{c-d}{c+d}}+\frac{\sqrt{c+d}}{\sqrt{c-d}} \right )=\frac{2c}{c^{2}\sqrt{2c}\sqrt{c+d}}=\frac{\sqrt{2}}{c\sqrt{c}\sqrt{c+d}}=\frac{\sqrt{2}}{c\sqrt{c^{2}+cd}}=\frac{\sqrt{2}}{2\sqrt{4+2\cdot \frac{1}{4}}}=\frac{1}{\sqrt{9}}=\frac{1}{3}\)

Ответ: \(\frac{1}{3}\)

Решение №16962: \(\left ( \left ( \sqrt{mn}-\frac{mn}{m+\sqrt{mn}} \right ):\frac{\sqrt[4]{mn}-\sqrt{n}}{m-n}-m\sqrt{n} \right )^{2}:\sqrt[3]{mn\sqrt{mn}}-\left ( \frac{m}{\sqrt{m^{4}-1}} \right )^{-2}=\left ( \sqrt{mn}\left ( 1-\frac{\sqrt{mn}}{\left ( \sqrt{m}+\sqrt{} \right )\sqrt{m}} \right ):\frac{\sqrt[4]{n}\left ( \sqrt[4]{m}-\sqrt[4]{n} \right )}{\left ( \sqrt{m}-\sqrt{n} \right )\left ( \sqrt{m}+\sqrt{n} \right )} -m\sqrt{n}\right )^{2}:\sqrt{mn}-\frac{m^{4}-1}{m^{2}}=\left ( m\sqrt[4]{n}\left ( \sqrt[4]{m}+\sqrt[4]{n} \right )-m\sqrt{n} \right )^{2}\cdot \frac{1}{\sqrt{mn}}-\frac{m^{4}-1}{m^{2}}=m^{2}-\frac{m^{4}-1}{m^{2}}=\frac{m^{4}-m^{4}+1}{m^{2}}=\frac{1}{m^{2}}\)

Ответ: \(\frac{1}{m^{2}}\)

Решение №16985: \(\frac{4a^{2}-b^{2}}{a^{6}-8b^{6}}\sqrt{a^{2}-2b\sqrt{a^{2}-b^{2}}}\cdot \frac{a^{4}+2a^{2}b^{2}+4b^{4}}{4a^{2}+4ab+b^{2}}\cdot \sqrt{a^{2}+2b\sqrt{a^{2}-b^{2}}}=\frac{\left ( 2a-b \right )\left ( 2a+b \right )}{\left ( a^{2} \right )^{3}-\left ( 2b^{2} \right )^{3}}\cdot \frac{a^{4}+2a^{2}b^{2}+4b^{4}}{\left ( 2a+b \right )^{2}}\cdot \sqrt{\left (a^{2}-2b\sqrt{a^{2}-b^{2}} \right )\left (a^{2}+2b\sqrt{a^{2}-b^{2}}\right )}=\frac{\left ( 2a-b \right )\left ( a^{4}+2a^{2}b^{2}+4b^{4} \right )}{\left ( a^{2}-2b^{2} \right )\left ( a^{4}+2a^{2}b^{2}+4b^{4} \right )\left ( 2a+b \right )}\cdot \sqrt{a^{4}-4b^{2}\left ( a^{2}-b^{2} \right )}=\frac{\left ( 2a-b \right )\left ( a^{2}-2b^{2} \right )}{\left ( a^{2}-2b^{2} \right )\left ( 2a+b \right )}=\frac{2a-b}{2a+b}=\frac{2\cdot \frac{4}{3}-0.25}{2\cdot \frac{4}{3}+0.25}=\frac{7.25}{8.75}=\frac{29}{35}\)

Ответ: \(\frac{29}{35}\)

Решение №16988: \(\frac{\sqrt[4]{7\sqrt[3]{54}+15\sqrt[3]{128}}}{\sqrt[3]{4\sqrt[4]{32}}+\sqrt[3]{9\sqrt[4]{162}}}=\frac{\sqrt[4]{7\cdot 3\sqrt[3]{2}+15\cdot 4\sqrt[3]{2}}}{\sqrt[3]{4\cdot 2\sqrt[4]{2}}+\sqrt[3]{9\cdot 3\sqrt[4]{2}}}=\frac{\sqrt[4]{81\sqrt[3]{2}}}{2\sqrt[3]{\sqrt[4]{2}}+3\sqrt[3]{\sqrt[4]{2}}}=\frac{3\sqrt[12]{2}}{5\sqrt[12]{2}}=\frac{3}{5}\)

Ответ: \(\frac{3}{5}\)

Решение №16990: \(\frac{5\sqrt[3]{4\sqrt[3]{192}}+7\sqrt[3]{18\sqrt[3]{81}}}{\sqrt[3]{12\sqrt[3]{24}}+6\sqrt[3]{375}}=\frac{5\sqrt[3]{4\cdot 4\sqrt[3]{3}}+7\sqrt[3]{18\cdot 3\sqrt[3]{3}}}{\sqrt[3]{12\cdot 2\sqrt[3]{3}}+6\cdot 5\sqrt[3]{3}}=\frac{31\sqrt[3]{2\sqrt[3]{3}}}{3\sqrt[3]{2\sqrt[3]{3}}}=\frac{31}{3}\)

Ответ: \(\frac{31}{3}\)

Решение №16992: \(\frac{\sqrt{x-4\sqrt{x-4}}+2}{\sqrt{x-4\sqrt{x-4}}-2}=\frac{\sqrt{x-4-4\sqrt{x-4}+4}+2}{\sqrt{x-4+4\sqrt{x-4}+4}-2}=\frac{\left | \sqrt{x-4}-2 \right |+2}{\sqrt{x-4}+2-2}=\frac{\left | \sqrt{x-4}-2 \right |+2}{\sqrt{x-4}}=\frac{4}{\sqrt{x-4}}-1;1\)

Ответ: \(\frac{4}{\sqrt{x-4}}-1;1\)

Решение №16998: \(\left ( \sqrt{ab}-ab\left ( a+\sqrt{ab} \right )^{-1} \right ):\left ( 2\left (\left ( ab \right )^{\frac{1}{2}}-b \right )\left ( a-b \right )^{-1}\right )=\left ( \sqrt{ab}-\frac{ab}{a+\sqrt{ab}} \right ):\frac{2\left ( \sqrt{ab}-b \right )}{a-b}=\left ( \sqrt{ab}-\frac{ab}{\sqrt{a}\left ( \sqrt{a}+\sqrt{b} \right )} \right ):\frac{2\sqrt{b}\left ( \sqrt{a}-\sqrt{b} \right )}{\left ( \sqrt{a}-\sqrt{b} \right )\left ( \sqrt{a}+\sqrt{b} \right )}=\sqrt{ab}\left ( 1-\frac{\sqrt{b}}{\sqrt{a}+\sqrt{b}} \right )\cdot \frac{\sqrt{a}+\sqrt{b}}{2\sqrt{b}}=\frac{a}{2}\)

Ответ: \(\frac{a}{2}\)

Решение №17027: \(\left ( \frac{a}{b}\sqrt[3]{b-\frac{4a^{6}}{b^{3}}}-a^{2}\sqrt[3]{\frac{b}{a^{6}}-\frac{4}{b^{3}}}+\frac{2}{ab}\sqrt[3]{a^{3}b^{4}-4a^{9}} \right ):\frac{\sqrt[3]{b^{2}-2a^{3}}}{b^{2}}=\left ( \frac{a}{b}\sqrt[3]{\frac{b^{4}-4a^{6}}{^{3}}}-a^{2}\sqrt[3]{\frac{b^{4}-4a^{6}}{a^{6}b^{3}}}+\frac{2}{ab}\sqrt[3]{a^{3}\left ( b^{4}-4a^{6} \right )} \right )\cdot \frac{b^{2}}{\sqrt[3]{b^{2}-2a^{3}}}=\left ( \frac{a\sqrt[3]{b^{4}-4a^{6}}}{b^{2}} -\frac{a^{2}\sqrt[3]b^{4}-4a^{6}}{{a^{2}b}}+\frac{2a\sqrt[3]{b^{4}-4a^{6}}}{ab}\right )\cdot \frac{b^{2}}{\sqrt[3]{b^{2}-2a^{3}}}=\frac{\sqrt[3]{\left ( b^{2}-2a^{3} \right )\left ( b^{2}+2a^{3} \right )\left ( a+b \right )}}{b^{2}}\cdot \frac{b^{2}}{\sqrt[3]{b^{2}-2a^{3}}}=\left ( a+b \right )\sqrt[3]{b^{2}+2a^{3}}\)

Ответ: \(\left ( a+b \right )\sqrt[3]{b^{2}+2a^{3}}\)

Решение №17028: \(4ab+\frac{\left ( 1+\left ( \frac{a}{b} \right )^{-3} \right )a^{3}}{\left ( \sqrt{a}+\sqrt{b} \right )^{2}-2\sqrt{ab}}-\frac{\left ( \frac{\sqrt{a}+\sqrt{b}}{2b\sqrt{a}} \right )^{-1}+\left ( \frac{\sqrt{a}+\sqrt{b}}{2a\sqrt{b}} \right )^{-1}}{\left ( \frac{a+\sqrt{ab}}{2} \right )^{-1}+\left ( \frac{b+\sqrt{ab}}{2} \right )^{-1}}=4ab+\frac{a^{3}+b^{3}}{a+b}-\frac{\frac{2b\sqrt{a}+2a\sqrt{b}}{\sqrt{a}+\sqrt{b}}}{\frac{2b+2\sqrt{ab}+2a+2\sqrt{ab}}{\left ( a+\sqrt{ab} \right )\left ( b+\sqrt{ab} \right )}}=4ab+a^{2}-ab+b^{2}-\sqrt{ab}\frac{\sqrt{ab}\left ( \sqrt{a}+\sqrt{b} \right )}{\left ( \sqrt{a}+\sqrt{b} \right )^{2}}=a^{2}+3ab+b^{2}-ab=a^{2}+2ab+b^{2}=\left ( a+b \right )^{2}\)

Ответ: \(\left ( a+b \right )^{2}\)

Решение №17034: \(\sqrt[4]{32\sqrt[3]{4}}+\sqrt[4]{64\sqrt[3]{\frac{1}{2}}}-3\sqrt[3]{2\sqrt[4]{2}}=\sqrt[4]{2^{5}\cdot 2^{\frac{2}{3}}}+\sqrt[4]{2^{6}\cdot 2^{-\frac{1}{3}}}-3\sqrt[3]{2\cdot 2^{\frac{1}{4}}}=2^{\frac{17}{12}}+2^{\frac{17}{12}}-3\cdot 2^{\frac{5}{12}}=2\cdot 2^{\frac{17}{12}}-3\cdot 2^{\frac{5}{12}}=2^{\frac{5}{12}}\left ( 4-3 \right )=2^{\frac{5}{12}}=\sqrt[12]{32}\)

Ответ: \(\sqrt[12]{32}\)

Решение №17036: \(\left ( \sqrt{\frac{\left ( 1-n \right )^{3}\sqrt{1+n}}{n}}\sqrt[3]{\frac{3n^{2}}{4-8n+4n^{2}}} \right )^{-1}:\sqrt[3]{\left ( \frac{3n\sqrt{n}}{2\sqrt{1-n^{2}}} \right )^{-1}}=\left ( \sqrt[6]{\left ( \frac{\left ( 1-n \right )^{3}\sqrt[3]{1+n}}{n^{3}} \right )^{3}}\sqrt[6]{\frac{3n^{2}}{4\left ( 1-2n+n^{2} \right )^{2}}} \right )^{-1}\sqrt[6]{\left ( \frac{3n\sqrt{n}}{2\sqrt{1-n^{2}}} \right )^{2}}=\left ( \sqrt[6]{\frac{\left ( 1-n \right )^{3}\left ( 1+n \right )9n^{4}}{n^{3}16\left ( 1-n \right )^{4}}} \right )^{-1}\sqrt[6]{\frac{9n^{3}}{4\left ( 1-n \right )\left ( 1+n \right )}}=\sqrt[6]{\frac{16\left ( 1-n \right )9n^{3}}{9n\left ( 1+n \right )4\left ( 1-n \right )\left ( 1+n \right )}}=\sqrt[6]{\frac{4n^{2}}{\left ( 1+n \right )^{2}}}=\sqrt[3]{\frac{2n}{1+n}}\)

Ответ: \(\sqrt[3]{\frac{2n}{1+n}}\)

Решение №17042: \(\sqrt{\frac{\sqrt{\left ( a-y \right )\left ( y-b \right )}+\sqrt{\left ( a+y \right )\left ( y+b \right )}}{\sqrt{\left ( a+y \right )\left ( y+b \right )}-\sqrt{\left ( a-y \right )\left ( y-b \right )}}}=\sqrt{\frac{\left ( \sqrt{\left ( a-y \right )\left ( y-b \right )}+\sqrt{\left ( a+y \right )\left ( y+b \right )} \right )\left ( \sqrt{\left ( a+y \right )\left ( y+b \right )}+\sqrt{\left ( a-y \right )\left ( y-b \right )} \right )}{\left ( \sqrt{\left ( a+y \right )\left ( y+b \right )}\sqrt{\left ( a-y \right )\left ( y-b \right )} \right )\left ( \sqrt{\left ( a+y \right )\left ( y+b \right )}+\sqrt{\left ( a-y \right )\left ( y-b \right )} \right )}}=\sqrt{\frac{-y^{2}+\left ( a+b \right )y-ab+2\sqrt{-y^{4}+\left ( a^{2}+b^{2} \right )y^{2}-a^{2}b^{2}}}{y^{2}+\left ( a+b \right )y+ab+y^{2}-\left ( a+b \right )y+ab}}=\sqrt{\frac{\left ( a+b \right )y+\sqrt{-y^{4}+\left ( a^{2}+b^{2} \right )y^{2}-a^{2}b^{2}}}{2y^{2}+2ab}}=\sqrt{\frac{\left ( a+b \right )\sqrt{ab}+\sqrt{-a^{2}b^{2}+\left ( a^{2}+b^{2} \right )ab-a^{2}b^{2}}}{ab+ab}}=\sqrt{\frac{\left ( a+b \right )\sqrt{ab}+\sqrt{ab\left ( a^{2}-2ab+b^{2} \right )}}{2ab}}=\sqrt{\frac{a+b+\left | a-b \right |}{2\sqrt{ab}}}=\sqrt[4]{\frac{b}{a}};\sqrt[4]{\frac{a}{b}}\)

Ответ: \(\sqrt[4]{\frac{b}{a}};\sqrt[4]{\frac{a}{b}}\)

Решение №17048: \(\frac{\left ( \sqrt{p^{3}}:\sqrt{p}+p \right )^{\frac{1}{4}}:\sqrt[8]{\left ( p-q \right )^{3}}}{\left ( \frac{\sqrt{q}}{\sqrt{p}-\sqrt{q}}-\sqrt{\frac{q}{p}}+1 \right )^{\frac{1}{4}}}=\frac{\sqrt[4]{\frac{\sqrt{p^{3}}}{\sqrt{p}}+p}:\sqrt[8]{\left ( p-q \right )^{3}}}{\sqrt[4]{\frac{\sqrt{q}}{\sqrt{p}-\sqrt{q}}-\frac{\sqrt{q}}{\sqrt{p}}+1}}=\sqrt[8]{\frac{\left ( \left ( \sqrt{p}+\sqrt{q} \right )\left ( p-\sqrt{pq}+q \right ) \right )^{2}\left ( \sqrt{p}-\sqrt{q} \right )^{2}}{\left ( p-q \right )^{3}\left ( p-\sqrt{pq}+q \right )^{2}}}=\sqrt[8]{\frac{\left ( \sqrt{p}+\sqrt{q} \right )^{2}\left ( \sqrt{p}-\sqrt{q} \right )^{2}}{\left ( p-q \right )^{3}}}=\sqrt[8]{\frac{\left ( p-q \right )^{2}}{\left ( p-q \right )^{3}}}=\sqrt[8]{\frac{1}{p-q}}-\frac{1}{\sqrt[8]{p-q}}\)

Ответ: \(\sqrt[8]{\frac{1}{p-q}}-\frac{1}{\sqrt[8]{p-q}}\)

Решение №17050: \(\frac{x^{\frac{3}{p}}-x^{\frac{3}{q}}}{\left ( x^{\frac{1}{p}}+x^{\frac{1}{q}} \right )^{2}-2x^{\frac{1}{q}}\left ( x^{\frac{1}{p}}+x^{\frac{1}{q}} \right )}+\frac{x^{\frac{2}{p}}}{x^{\frac{q-p}{pq}}+1}=\frac{\left ( x^{\frac{1}{p}}-x^{\frac{1}{q}} \right )\left ( x^{\frac{2}{p}}+x^{\frac{1}{p}}x^{\frac{1}{q}}+x^{\frac{2}{q}} \right )}{\left ( x^{\frac{1}{p}}+x^{\frac{1}{q}} \right )\left ( x^{\frac{1}{p}}-x^{\frac{1}{q}} \right )}+\frac{x^{\frac{1}{p}}}{\frac{x^{\frac{1}{p}}}{x^{\frac{1}{q}}}+1}=x^{\frac{1}{p}}+x^{\frac{1}{q}}=\sqrt[p]{x}+\sqrt[q]{x}\)

Ответ: \(\sqrt[p]{x}+\sqrt[q]{x}\)

Решение №17051: \(\frac{2a\left ( a+2b+\sqrt{a^{2}+4ab} \right )}{\left ( a+\sqrt{a^{2}+4ab} \right )\left ( a+4b+\sqrt{a^{2}+4ab} \right )}=\frac{a+\sqrt{a^{2}+4ab}}{a+4b+\sqrt{a^{2}+4ab}}=\frac{a^{2}+4ab-a\sqrt{a^{2}+4ab}+a\sqrt{a^{2}+4ab}+4b\sqrt{a^{2}+4ab}-a^{2}-4ab}{\left ( a+4b \right )^{2}-\left ( \sqrt{a^{2}}+4ab \right )^{2}}=\frac{4b\sqrt{a^{2}+4ab}}{a^{2}+8ab+16b^{2}-a^{2}+4ab}=\frac{4b\sqrt{a^{2}+4ab}}{4ab+16b^{2}}=\frac{4b\sqrt{a^{2}+4ab}}{4b\left ( a+4b \right )}=\frac{\sqrt{a\left ( a+4b \right )}}{a+4b}=\sqrt{\frac{a\left ( a+4b \right )}{\left ( a+4b \right )^{2}}}=\sqrt{\frac{a}{a+4b}}\)

Ответ: \(\sqrt{\frac{a}{a+4b}}\)

Решение №17071: \(\frac{\sqrt{\left ( 3x+2 \right )^{2}-24x}}{3\sqrt{x}-\frac{2}{\sqrt{x}}}=\frac{\sqrt{9x^{2}+12x+4-24x}}{\frac{3x-2}{\sqrt{x}}}=\frac{\sqrt{9x^{2}-12x+4}\sqrt{x}}{3x-2}=\frac{\sqrt{\left ( 3x-2 \right )^{2}}\sqrt{x}}{3x-2}=\frac{\left | 3x-2 \right |\sqrt{x}}{3x-2}=-\sqrt{x};\sqrt{x}\)

Ответ: \(-\sqrt{x};\sqrt{x}\)

Решение №17086: \(\left ( \frac{9-4a^{-2}}{3a^{-\frac{1}{2}}}+2a^{-\frac{3}{2}}-\frac{1+a^{-1}-6a^{-2}}{a^{-\frac{1}{2}}+3a^{-\frac{3}{2}}} \right )^{4}=\left ( \frac{9a^{2}-4}{a^{2}}\cdot \frac{a^{\frac{3}{2}}}{3a+2}-\frac{a^{2}+a-6}{a^{2}}\cdot \frac{a^{\frac{3}{2}}}{a+3} \right )^{4}=\left ( \frac{3a-2}{a^{\frac{1}{2}}}-\frac{a-2}{a^{\frac{1}{2}}} \right )^{4}=\left ( \frac{2a}{a^{\frac{1}{2}}} \right )^{4}=\left ( 2a^{\frac{1}{2}} \right )^{4}=16a^{2}\)

Ответ: \(16a^{2}\)