Решение №16987: \(\left ( x+1 \right )\left ( x+2 \right )\left ( x+3 \right )\left ( x+4 \right ); x=\frac{\sqrt{7}-5}{2};=\left (\frac{\sqrt{7}-5}{2}+1 \right )\left ( \frac{\sqrt{7}-5}{2}+2 \right )\left ( \frac{\sqrt{7}-5}{2}+3 \right )\left ( \frac{\sqrt{7}-5}{2}+4 \right )=\left ( \left ( \frac{\sqrt{7}-5}{2} \right )^{2}+5\frac{\sqrt{7}-5}{2}+4 \right )\left ( \left ( \frac{\sqrt{7}-5}{2} \right )^{2}+5\frac{\sqrt{7}-5}{2}+6 \right )=\left ( \frac{-9}{2} \right )^{2}+10\left ( \frac{-9}{2}+24 \right )=-\frac{3}{4}\)

Ответ: \(-\frac{3}{4}\)

Решение №16988: \(\frac{\sqrt[4]{7\sqrt[3]{54}+15\sqrt[3]{128}}}{\sqrt[3]{4\sqrt[4]{32}}+\sqrt[3]{9\sqrt[4]{162}}}=\frac{\sqrt[4]{7\cdot 3\sqrt[3]{2}+15\cdot 4\sqrt[3]{2}}}{\sqrt[3]{4\cdot 2\sqrt[4]{2}}+\sqrt[3]{9\cdot 3\sqrt[4]{2}}}=\frac{\sqrt[4]{81\sqrt[3]{2}}}{2\sqrt[3]{\sqrt[4]{2}}+3\sqrt[3]{\sqrt[4]{2}}}=\frac{3\sqrt[12]{2}}{5\sqrt[12]{2}}=\frac{3}{5}\)

Ответ: \(\frac{3}{5}\)

Решение №16989: \(\frac{x\left | x-3 \right |+x^{2}-9}{2x^{3}-3x^{2}-9x}=\frac{x\left | x-3 \right |+x^{2}-9}{x\left ( 2x^{2}-3x-9 \right )}=\frac{-x\left ( x-3 \right )+x^{2}-9}{x\left ( 2x^{2}-3x-9 \right )};\frac{x\left ( x-3 \right )+x^{2}-9}{x\left ( 2x^{2}-3x-9 \right )}= \frac{3\left ( x-3 \right )}{x\left ( 2x+3 \right )\left ( x-3 \right )};\frac{2x^{2}-3x-9}{x\left ( 2x^{2}-3x-9 \right )}=\frac{3}{x\left ( 2x+3 \right )};\frac{1}{x}\)

Ответ: \(\frac{3}{x\left ( 2x+3 \right )};\frac{1}{x}\)

Решение №16990: \(\frac{5\sqrt[3]{4\sqrt[3]{192}}+7\sqrt[3]{18\sqrt[3]{81}}}{\sqrt[3]{12\sqrt[3]{24}}+6\sqrt[3]{375}}=\frac{5\sqrt[3]{4\cdot 4\sqrt[3]{3}}+7\sqrt[3]{18\cdot 3\sqrt[3]{3}}}{\sqrt[3]{12\cdot 2\sqrt[3]{3}}+6\cdot 5\sqrt[3]{3}}=\frac{31\sqrt[3]{2\sqrt[3]{3}}}{3\sqrt[3]{2\sqrt[3]{3}}}=\frac{31}{3}\)

Ответ: \(\frac{31}{3}\)

Решение №16991: \(\frac{1}{\sqrt{x^{2}+4x+4}}+\left | x-2 \right |=\frac{1}{\sqrt{\left ( x+2 \right )^{2}}}+\left | x-2 \right |=\frac{1}{\left | x+2 \right |}+\left | x-2 \right |=\frac{1+\left | x^{2}-4 \right |}{\left | x+2 \right |}=\frac{1+x^{2}-4}{-\left ( x+2 \right )};\frac{1-\left (x^{2}-4 \right )}{ x+2 };\frac{1+x^{2}-4}{ x+2}=\frac{3-x^{2}}{x+2};\frac{5-x^{2}}{x+2};\frac{x^{2}-3}{x+2}\)

Ответ: \(\frac{3-x^{2}}{x+2};\frac{5-x^{2}}{x+2};\frac{x^{2}-3}{x+2}\)

Решение №16992: \(\frac{\sqrt{x-4\sqrt{x-4}}+2}{\sqrt{x-4\sqrt{x-4}}-2}=\frac{\sqrt{x-4-4\sqrt{x-4}+4}+2}{\sqrt{x-4+4\sqrt{x-4}+4}-2}=\frac{\left | \sqrt{x-4}-2 \right |+2}{\sqrt{x-4}+2-2}=\frac{\left | \sqrt{x-4}-2 \right |+2}{\sqrt{x-4}}=\frac{4}{\sqrt{x-4}}-1;1\)

Ответ: \(\frac{4}{\sqrt{x-4}}-1;1\)

Решение №16993: \(\frac{\sqrt{\left ( 1+\frac{b}{a} \right )^{2}-\frac{4b+1}{a}}\left ( \sqrt{a}+\sqrt{b+\sqrt{a}} \right )^{-\frac{1}{2}}}{\sqrt{a-b+\sqrt{a}}\sqrt{\sqrt{a}-\sqrt{b+\sqrt{a}}}}=\frac{\frac{\sqrt{\left ( a-b \right )^{2}-a}}{a}}{\sqrt{\left ( a-b+\sqrt{a} \right )\left ( a-b-\sqrt{a} \right )}}=\frac{\sqrt{\left ( a-b \right )^{2}-a}}{a\sqrt{\left ( a-b \right )^{2}-a}}=\frac{1}{a}=\frac{1}{2.25}=\frac{1}{\frac{9}{4}}=\frac{4}{9}\)

Ответ: \(\frac{4}{9}\)

Решение №16994: \(\frac{4-\sqrt[3]{a^{2}}}{\left ( 2+\sqrt[3]{ab} \right )^{2}-\left ( \sqrt[3]{a}+2\sqrt[3]{b} \right )^{2}}=\frac{4-\sqrt[3]{a^{2}}}{\left ( 4-\sqrt[3]{a^{2}} \right )-\sqrt[3]{b^{2}\left ( 4-\sqrt[3]{a^{2}} \right )}}=\frac{4-\sqrt[3]{a^{2}}}{\left ( 4-\sqrt[3]{a^{2}} \right )\left ( 1-\sqrt[3]{a^{2}} \right )}=\frac{1}{1-\sqrt[3]{a^{2}}}=\frac{1}{1-\sqrt[3]{0.008}}=\frac{1}{1-0.2}=\frac{1}{0.8}=\frac{5}{4}\)

Ответ: \(\frac{5}{4}\)

Решение №16995: \(\sqrt{\frac{x}{x-a^{2}}}:\left ( \frac{\sqrt{x}-\sqrt{x-a^{2}}}{\sqrt{x}+\sqrt{x-a^{2}}}- \frac{\sqrt{x}+\sqrt{x-a^{2}}}{\sqrt{x}-\sqrt{x-a^{2}}}\right )=\sqrt{\frac{x}{x-a^{2}}}:\left ( \frac{\left ( \sqrt{x}-\sqrt{x-a^{2}} \right )^{2}-\left ( \sqrt{x}+\sqrt{x-a^{2}} \right )^{2}}{\left ( \sqrt{x}+\sqrt{x-a^{2}} \right )\left ( \sqrt{x}-\sqrt{x-a^{2}} \right )} \right )=\sqrt{\frac{x}{x-a^{2}}}:\frac{-4\sqrt{x\left ( x-a^{a} \right )}}{x-x+a^{2}}=-\frac{a^{2}}{4\left ( x-a^{2} \right )}=\frac{a^{2}}{4\left ( a^{2}-x \right )}\)

Ответ: \(\frac{a^{2}}{4\left ( a^{2}-x \right )}\)

Решение №16996: \(\frac{2a^{4}+a^{3}+4a^{2}+a+2}{2a^{3}-a^{2}+a-2}=\frac{\left ( 2a^{4}+2a^{2} \right )+\left ( a^{3}+a \right )+\left ( 2a^{2}+2 \right )}{\left ( 2a^{3}-2a^{2} \right )+\left ( a^{2}-a \right )+\left ( 2a-2 \right )}=\frac{\left ( a^{2}+1 \right )\left ( 2a^{2}+a+2 \right )}{\left ( a-1 \right )\left ( 2a^{2}+a+2 \right )}=\frac{a^{2}+1}{a-1}\)

Ответ: \(\frac{a^{2}+1}{a-1}\)