Решение №16977: \(\left ( \left ( \sqrt[4]{p}-\sqrt[4]{q} \right )^{-2} +\left ( \sqrt[4]{p} +\sqrt[4]{q}\right )^{-2}\right ):\frac{\sqrt{p}+\sqrt{q}}{p-q}=\left ( \frac{1}{\left ( \sqrt[4]{p}-\sqrt[4]{q} \right )^{2}} +\frac{1}{\left ( \sqrt[4]{p}+\sqrt[4]{q} \right )^{2}}\right )\cdot \frac{p-q}{\sqrt{p}+\sqrt{q}}=\frac{\left ( \sqrt[4]{p}+\sqrt[4]{q} \right )^{2}+\left ( \sqrt[4]{p}-\sqrt[4]{q} \right )^{2}}{\sqrt{p}-\sqrt{q}}\cdot \frac{\left ( \sqrt{p}-\sqrt{q} \right )\left ( \sqrt{p}+\sqrt{q} \right )}{\sqrt{p}+\sqrt{q}}=\frac{\sqrt{p}+2\sqrt[4]{pq}+\sqrt{q}+\sqrt{p}-2\sqrt[4]{pq}+\sqrt{q}}{\sqrt{p}-\sqrt{q}}=\frac{2\left ( \sqrt{p}+\sqrt{q} \right )}{\sqrt{p}-\sqrt{q}}=\frac{2\left ( \sqrt{p}+\sqrt{q} \right )\left ( \sqrt{p}+\sqrt{q} \right )}{\left ( \sqrt{p}-\sqrt{q} \right )\left ( \sqrt{p}-\sqrt{q} \right )}=\frac{2\left ( \sqrt{p}+\sqrt{q} \right )^{2}}{p-q}\)

Ответ: \(\frac{2\left ( \sqrt{p}+\sqrt{q} \right )^{2}}{p-q}\)

Решение №16978: \(\frac{a}{b^{3}-1}-\frac{b}{a^{3}-1}=\frac{\left ( a^{4}-b^{4} \right )-\left ( a-b \right )}{a^{3}b^{3}-\left ( a^{3}+b^{3} \right )+1}=\frac{\left ( a-b \right )\left ( 1-2ab-1 \right )}{a^{3}b^{3}-\left ( a^{3}+b^{3} \right )+1}=\frac{\left ( a-b \right )\left ( -2ab \right )}{a^{2}b^{3}+3ab}=\frac{2\left ( b-a \right )}{a^{2}b^{2}+3}\)

Ответ: \(\frac{2\left ( b-a \right )}{a^{2}b^{2}+3}\)

Решение №16979: \(\frac{\left ( \sqrt[3]{\left (r^{2}+4}\right )\cdot \sqrt{1+\frac{4}{r^{2}}}-\sqrt[3]{\left ( r^{2}+4 \right )\sqrt{1-\frac{4}{r^{2}}}} \right )^{2}}{r^{2}-\sqrt{r^{4}-16}}=\frac{2\left ( r^{2}-\sqrt[3]{\left ( r^{4}-16 \right )^{\frac{3}{2}}} \right )}{\sqrt[3]{r^{2}}\left ( r^{2}-\sqrt{r^{4}-16} \right )}=\frac{2}{\sqrt[3]{r^{2}}}=\frac{2\sqrt[3]{r}}{r}\)

Ответ: \(\frac{2\sqrt[3]{r}}{r}\)

Решение №16980: \(\sqrt{\frac{2a}{\left ( 1+a \right )\sqrt[3]{1+a}}}\cdot \sqrt[3]{\frac{4+\frac{8}{a}+\frac{4}{a^{2}}}{\sqrt{2}}}=\sqrt[6]{\left ( \frac{2a}{\left ( 1+a \right )\sqrt[3]{1+a}} \right )^{3}}\cdot \sqrt[6]{\left ( \frac{\frac{4+\frac{8}{a}+\frac{4}{a^{2}}}{\sqrt{2}}} \right )}=\sqrt[6]{\frac{8a^{3}}{\left ( 1+a \right )^{4}}\cdot \sqrt[6]{\frac{8\left ( 1+a \right )^{4}}{a^{4}}}}=\sqrt[6]{\frac{64}{a}}=\frac{2\sqrt[6]{a^{5}}}{a}\)

Ответ: \(\frac{2\sqrt[6]{a^{5}}}{a}\)

Решение №16981: \(\frac{z^{3}}{3}-z=\frac{\sqrt[3]{\sqrt{3}+\sqrt{2}}+\sqrt[3]{\sqrt{3}-\sqrt{2}}}{3}-\left ( \sqrt[3]{\sqrt{3}+\sqrt{2}}+\sqrt[3]{\sqrt{3}-\sqrt{2}} \right )=\frac{2\sqrt{3}+3\sqrt[3]{\left ( 3-2 \right )\left ( \sqrt{3}+\sqrt{2} \right )}-3\sqrt[3]{\left ( 3-2 \right )\left ( \sqrt{3}-\sqrt{2} \right )}-3\sqrt[3]{\sqrt{3}+\sqrt{2}}-3\sqrt[3]{\sqrt{3}-\sqrt{2}}}{3}=\frac{2\sqrt{3}+3\sqrt[3]{\sqrt{3}+\sqrt{2}}+3\sqrt[3]{\sqrt{3}-\sqrt{2}}-3\sqrt[3]{\sqrt{3}+\sqrt{2}}-3\sqrt[3]{\sqrt{3}-\sqrt{2}}}{3}=\frac{2\sqrt{3}}{3}; x^{3}+3x=\left ( \sqrt[3]{\sqrt{5}+2}-\sqrt[3]{\sqrt{5}-2} \right )^{3}+3\left ( \sqrt[3]{\sqrt{5}+2}-\sqrt[3]{\sqrt{5}-2} \right )=\sqrt{5}+2-3\sqrt[3]{\left ( \sqrt{5}+2 \right )^{2}\left ( \sqrt{5}-2 \right )}+3\sqrt[3]{\left ( \sqrt{5}+2 \right )\left ( \sqrt{5}-2 \right )^{2}}-\sqrt{5}+2+3\sqrt[3]{\sqrt{5}+2}-3\sqrt[3]{\sqrt{5}-2}=4-3\sqrt[3]{\sqrt{5}+2}+3\sqrt[3]{\sqrt{5}-2}+3\sqrt[3]{\sqrt{5}+2}-3\sqrt[3]{\sqrt{5}-2}=4\)

Ответ: \(\frac{2\sqrt{3}}{3}; 4\)

Решение №16982: \(\frac{6}{\sqrt{2}+\sqrt{3}+\sqrt{5}}=\frac{6\left ( \sqrt{2}+\sqrt{3}-\sqrt{5} \right )}{\left ( \sqrt{2}+\sqrt{3}+\sqrt{5} \right )\left ( \sqrt{2}+\sqrt{3}-\sqrt{5} \right )}=\frac{6\left ( \sqrt{2}+\sqrt{3}-\sqrt{5} \right )}{2+3-5+2\sqrt{2*3}}=\frac{\sqrt{4*3}+\sqrt{9*2}-\sqrt{30}}{2}=\frac{2\sqrt{3}+3\sqrt{2}-\sqrt{30}}{2}\)

Ответ: \(\frac{2\sqrt{3}+3\sqrt{2}-\sqrt{30}}{2}\)

Решение №16983: \(\left ( \left ( 1-p^{2} \right )^{-\frac{1}{2}} -\left ( 1+p^{2} \right )^{-\frac{1}{2}} \right )^{2}+2\left ( 1-p^{4} \right )^{-\frac{1}{2}}=\left ( \frac{1}{\sqrt{1-p^{2}}}-\frac{1}{\sqrt{1+p^{2}}} \right )^{2}+\frac{2}{\sqrt{1-p^{4}}}=\left ( \frac{\sqrt{1+p^{2}}-\sqrt{1-p^{2}}}{\sqrt{1-p^{4}}} \right )^{2}+\frac{2}{\sqrt{1-p^{4}}}=\frac{1+p^{2}-2\sqrt{1-p^{4}}+1-p^{2}}{1-p^{4}}+\frac{2}{\sqrt{1-p^{4}}}=\frac{2-2\sqrt{1-p^{4}}}{1-p^{4}}+\frac{2}{\sqrt{1-p^{4}}}=\frac{2-2\sqrt{1-p^{4}}+2\sqrt{1-p^{4}}}{1-p^{4}}=\frac{2}{1-p^{4}}\)

Ответ: \(\frac{2}{1-p^{4}}\)

Решение №16984: \(\frac{x\left ( x^{2}-a^{2} \right )^{-\frac{1}{2}}+1}{a\left ( x-a \right )^{-\frac{1}{2}}+\left ( x+a \right )^{\frac{1}{2}}}:\frac{a^{2}\sqrt{x+a}}{x-\left ( x^{2}-a^{2} \right )^{\frac{1}{2}}}+\frac{1}{x^{2}-ax}=\frac{\frac{x}{\sqrt{x^{2}-a^{2}}+1}}{\frac{a}{\sqrt{x-a}}+\sqrt{x-a}}:\frac{a^{2}\sqrt{x+a}}{x-\sqrt{x^{2}-a^{2}}}+\frac{1}{x\left ( x-a \right )}=\frac{\left ( x+\sqrt{x^{2}-a^{2}}\sqrt{x-a} \right )}{\sqrt{\left ( x+a \right )\left ( x-a \right )}\left ( a+x-a \right )}\cdot \frac{x-\sqrt{x^{2}-a^{2}}}{a^{2}\sqrt{x+a}}+\frac{1}{x\left ( x-a \right )}=\frac{x^{2}-x^{2}+a^{2}}{a^{2}x\left ( x+a \right )}+\frac{1}{\left ( x-a \right )}=\frac{1}{\left ( x+a \right )}+\frac{1}{\left ( x-a \right )}=\frac{2}{x^{2}-a^{2}}\)

Ответ: \(\frac{2}{x^{2}-a^{2}}\)

Решение №16985: \(\frac{4a^{2}-b^{2}}{a^{6}-8b^{6}}\sqrt{a^{2}-2b\sqrt{a^{2}-b^{2}}}\cdot \frac{a^{4}+2a^{2}b^{2}+4b^{4}}{4a^{2}+4ab+b^{2}}\cdot \sqrt{a^{2}+2b\sqrt{a^{2}-b^{2}}}=\frac{\left ( 2a-b \right )\left ( 2a+b \right )}{\left ( a^{2} \right )^{3}-\left ( 2b^{2} \right )^{3}}\cdot \frac{a^{4}+2a^{2}b^{2}+4b^{4}}{\left ( 2a+b \right )^{2}}\cdot \sqrt{\left (a^{2}-2b\sqrt{a^{2}-b^{2}} \right )\left (a^{2}+2b\sqrt{a^{2}-b^{2}}\right )}=\frac{\left ( 2a-b \right )\left ( a^{4}+2a^{2}b^{2}+4b^{4} \right )}{\left ( a^{2}-2b^{2} \right )\left ( a^{4}+2a^{2}b^{2}+4b^{4} \right )\left ( 2a+b \right )}\cdot \sqrt{a^{4}-4b^{2}\left ( a^{2}-b^{2} \right )}=\frac{\left ( 2a-b \right )\left ( a^{2}-2b^{2} \right )}{\left ( a^{2}-2b^{2} \right )\left ( 2a+b \right )}=\frac{2a-b}{2a+b}=\frac{2\cdot \frac{4}{3}-0.25}{2\cdot \frac{4}{3}+0.25}=\frac{7.25}{8.75}=\frac{29}{35}\)

Ответ: \(\frac{29}{35}\)

Решение №16986: \(\frac{\left ( z-1 \right )\left ( z+2 \right )\left ( z-3 \right )\left ( z+4 \right )}{23}; x=\frac{\sqrt{3}-1}{2};=\frac{\left (\frac{\sqrt{3}-1}{2}-1 \right )\left ( \frac{\sqrt{3}-1}{2}+2 \right )\left ( \frac{\sqrt{3}-1}{2}-3 \right )\left ( \frac{\sqrt{3}-1}{2}+4 \right )}{23}=\frac{\left ( \left ( \frac{\sqrt{3}-1}{2} \right )^{2}+\frac{\sqrt{3}-1}{2}-2 \right )\left ( \left ( \frac{\sqrt{3}-1}{2} \right )^{2}+\frac{\sqrt{3}-1}{2}-12 \right )}{23}=\frac{\left ( \frac{1}{2} \right )^{2}-14\frac{1}{2}+24}{23}=\frac{\frac{1}{4}-7+24}{23}=\frac{3}{4}\)

Ответ: \(\frac{3}{4}\)