Решение №16094: \(\left ( \frac{\sqrt{1+x}}{\sqrt{1+x}-\sqrt{1-x}}+\frac{1-x}{\sqrt{1-x^{2}}-1+x} \right )\left ( \sqrt{\frac{1}{x^{2}}-1}-\frac{1}{x} \right )=\frac{\sqrt{1+x}+\sqrt{1-x}}{\sqrt{1+x}-\sqrt{1-x}}\cdot \frac{\sqrt{1-x^{2}}-1}{x}=\frac{\left ( \sqrt{1+x}+\sqrt{1-x} \right )\left ( \sqrt{1+x}+\sqrt{1-x} \right )}{\left ( \sqrt{1+x}-\sqrt{1-x} \right )\left ( \sqrt{1+x}+\sqrt{1-x} \right )}\cdot \frac{\sqrt{1-x^{2}}-1}{x}=\frac{1+x+2\sqrt{1-x^{2}}+1-x}{1+x-1+x}\cdot \frac{\sqrt{1-x^{2}}-1}{x}=\frac{\left ( \sqrt{1-x^{2}} \right )^{2}-1}{x^{2}}=\frac{1-x^{2}-1}{x^{2}}=-\frac{x^{2}}{x^{2}}=-1\)

Ответ: -1

Решение №16095: \(\frac{2x^{-\frac{1}{3}}}{x^{\frac{2}{3}}-3x^{-\frac{1}{3}}}-\frac{x^{\frac{2}{3}}}{x^{\frac{5}{3}}-x^{\frac{2}{3}}}-\frac{x+1}{x^{2}-4x+3}=\frac{2x^{-\frac{1}{3}}}{x^{-\frac{1}{3}}-\left ( x-3 \right )}-\frac{x^{\frac{2}{3}}}{x^{\frac{2}{3}}-\left ( x-1 \right )}-\frac{x+1}{\left ( x-1 \right )\left ( x-3 \right )}=\frac{2}{x-3}-\frac{1}{x-1}-\frac{x+1}{\left ( x-1 \right )\left ( x-3 \right )}=\frac{2x-2-x+3-x-1}{\left ( x-1 \right )\left ( x-3 \right )}=\frac{0}{\left ( x-1 \right )\left ( x-3 \right )}=0\)

Ответ: 0

Решение №16096: \(\frac{m^{\frac{4}{3}}-27m^{\frac{1}{3}}\cdot n}{m^{\frac{2}{3}}+3\sqrt[3]{mn}+9n^{\frac{2}{3}}}:\left ( 1-3\sqrt[3]{\frac{n}{m}} \right )-\sqrt[3]{m^{2}}=\frac{m^{\frac{1}{3}}\left ( m-27n \right )}{m^{\frac{2}{3}}+3m^{\frac{1}{3}}n^{\frac{1}{3}}+9n^{\frac{2}{3}}}:\frac{\sqrt[3]{m}-3\sqrt[3]{n}}{\sqrt[3]{m}}-m^{\frac{2}{3}}=m^{\frac{2}{3}}-m^{\frac{2}{3}}=0\)

Ответ: 0

Решение №16097: \(2\sqrt{40\sqrt{12}}+3\sqrt{5\sqrt{48}}-2\sqrt[4]{75}-4\sqrt{15\sqrt{27}}=2\sqrt{40\sqrt{4\cdot 3}}+3\sqrt{5\sqrt{16\cdot 3}}-2\sqrt[4]{25\cdot 3}-4\sqrt{15\sqrt{9\cdot 3}}=8\sqrt{5\sqrt{3}}+6\sqrt{5\sqrt{3}}-2\sqrt{5\sqrt{3}}-12\sqrt{5\sqrt{3}}=14\sqrt{5\sqrt{3}}-14\sqrt{5\sqrt{3}}=0\)

Ответ: 0

Решение №16098: \(5\sqrt[3]{6\sqrt{32}}-3\sqrt[3]{9\sqrt{162}}-11\sqrt[6]{18}+2\sqrt[3]{75\sqrt{50}}=5\sqrt[3]{6\sqrt{16*2}}-3\sqrt[3]{9\sqrt{81*2}}-11\sqrt[6]{9*2}+2\sqrt[3]{75\sqrt{25*2}}=5*2\sqrt[3]{3\sqrt{2}}-3*3\sqrt[3]{3\sqrt{2}}-11\sqrt[3]{3\sqrt{2}}+2*5\sqrt[3]{3\sqrt{2}}=10\sqrt[3]{3\sqrt{2}}-20\sqrt[3]{3\sqrt{2}}+10\sqrt[3]{3\sqrt{2}}=0\)

Ответ: 0

Решение №16099: \(\frac{x^{3}-a^{-\frac{2}{3}}b^{-1}\left ( a^{2}+b^{2} \right )x+b^{\frac{1}{2}}}{b^{\frac{3}{2}}x^{2}}; x=a^{\frac{2}{3}}b^{-\frac{1}{2}};=\frac{\left (a^{\frac{2}{3}}b^{-\frac{1}{2}} \right )^{3}-a^{\frac{2}{3}}b^{-1}\left ( a^{2}+b^{2} \right )a^{\frac{2}{3}}b^{-\frac{1}{2}}+b^{\frac{1}{2}}}{b^{\frac{3}{2}}\left ( a^{\frac{2}{3}}b^{-\frac{1}{2}} \right )^{2}}=\frac{\frac{a^{2}-a^{2}-b^{2}+b^{2}}{b^{\frac{3}{2}}}}{b^{\frac{1}{2}}a^{\frac{4}{3}}}=0\)

Ответ: 0

Решение №16100: \(\frac{1-b}{\sqrt{b}}\cdot x^{2}-2x+\sqrt{b}; x=\frac{\sqrt{b}}{1-\sqrt{b}};=\frac{1-b}{\sqrt{b}}\left ( \frac{\sqrt{b}}{1-\sqrt{b}} \right )^{2}-2\cdot \frac{\sqrt{b}}{1-\sqrt{b}}+\sqrt{b}=\frac{\left ( 1-\sqrt{b} \right )\left ( 1+\sqrt{b} \right )}{\sqrt{b}}\cdot \frac{b}{\left ( 1-\sqrt{b} \right )^{2}}-\frac{2\sqrt{b}}{1-\sqrt{b}}+\sqrt{b}=\frac{\left ( 1+\sqrt{b} \right )\sqrt{b}}{1-\sqrt{b}}-\frac{2\sqrt{b}}{1-\sqrt{b}}+\sqrt{b}=\frac{\sqrt{b}+b-2\sqrt{b}+\sqrt{b}-b}{1-\sqrt{b}}=0\)

Ответ: 0

Решение №16101: \(\left ( \sqrt[3]{\frac{8z^{3}+24z^{2}+18z}{2z-3}}-\sqrt[3]{\frac{8z^{2}-24z^{2}+18z}{2z+3}} \right )-\left ( \frac{1}{2}\sqrt[3]{\frac{2z}{27}}-\frac{1}{6z} \right )^{-1}=\sqrt[3]{\frac{2z\left ( 2z+3 \right )^{2}}{2z-3}}-\sqrt[3]{\frac{2z\left ( 2z-3 \right )^{2}}{2z+3}}-2\sqrt[3]{\frac{54z}{4z^{2}-9}}= \sqrt[3]{\frac{2z\left ( 2z+3 \right )^{2}}{2z-3}}-\sqrt[3]{\frac{2z\left ( 2z-3 \right )^{2}}{2z+3}}-\frac{2\sqrt[3]{54z}}{\sqrt[3]{\left ( 2z-3 \right )\left ( 2z+3 \right )}} =\frac{\sqrt[3]{2z}\left ( 2z+3-2z+3-6 \right )}{\sqrt[3]{4z^{2}-9}}=\frac{\sqrt[3]{2z}\cdot 0}{\sqrt[3]{4z^{2}-9}}=0\)

Ответ: 0

Решение №16102: \(\left ( \frac{1+1+x^{2}}{2x+x^{x}} +2-\frac{1-x+x^{2}}{2x-x^{2}}\right )^{-1}\cdot \left ( 5-2x^{2} \right )=\left ( \frac{1+1+x^{2}}{x\left ( 2+x \right )} +2-\frac{1-x+x^{2}}{x\left ( 2-x \right )}\right )^{-1}\cdot \left ( 5-2x^{2} \right )=\left ( \frac{2+2x+2x^{2}-x-x^{2}-x^{3}+8x-2x^{3}-2+2x-2x^{2}-x+x^{2}-x^{3}}{x\left ( 4-x^{2} \right )} \right )^{-1}\cdot \left ( 5-2x^{2} \right )=\left ( \frac{10x-4x^{3}}{x\left ( 4-x^{2} \right )} \right )^{-1}\cdot \left ( 5-2x^{2} \right )=\left ( \frac{2x\left ( 5-2x^{2} \right )}{x\left ( 4-x^{2} \right )} \right )^{-1}\cdot \left ( 5-2x^{2} \right )=\frac{4-x^{2}}{2}=\frac{4-\left ( \sqrt{3.92} \right )^{2}}{2}=\frac{0.08}{2}=0.04\)

Ответ: 0.04

Решение №16103: \(\frac{\frac{1}{a}-\frac{1}{b+c}}{\frac{1}{a}+\frac{1}{b+c}}\cdot \left ( 1+\frac{b^{2}+c^{2}-a^{2}}{2bc} \right ):\frac{a-b-c}{abc}=\frac{\left ( b+c-a \right )a\left ( b+c \right )}{a\left ( b+c \right )\left ( b+c+a \right )}\cdot \frac{\left ( b^{2}+2bc+c^{2} \right )-a^{2}}{2bc}\cdot \frac{abc}{a-b-c}=\frac{b+c-a}{b+c+a}\cdot \frac{\left ( b+c \right )^{2}-a^{2}}{2}\cdot \frac{ab}{a-b-c}=\frac{-\left ( a-b-c \right )\left ( b+c+a \right )\left ( b+c-a \right )a}{2\left ( b+c+a \right )\left ( a-b-c \right )}=\frac{-\left ( b+c-a \right )a}{2}=\frac{\left ( a-b-c \right )a}{2}=\frac{\left ( 0.02+11.05-1.07 \right )\cdot 0.02}{2}=0.1\)

Ответ: 0.1